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 Help with a Red/Green positive/negative hatched graph? 1

 Josh McCormick 2020-07-03 15:38:13 I'm wanting to create a filled hatch graph (with a black outline and zero line) where everything above zero is filled in green and everything below zero is filled in red. I figured out some code that worked perfectly.... except for where they meet in the middle. There is some sloppy overspray. Is there a better way to do what I want? And please, forgive my code. This is my third day with the product: EXAMPLE IMAGE ------------------------- https://i.imgur.com/KzrkxXX.png MY CODE ----------------------------------- // Pull Enhanced SRM Data (in beta - to be published) based upon a 50 period lookback a = Srme(50); // Plot the top half of the graph in a nice green hatched pattern (positive numbers) Plot((a>0)*a, "Bulls Only", colorGreen|108, ChartLine, StyleWidth2); SetHatchBrush("Percent20", colorWhite|255|colorMintCream|255|161); // Plot the bottom half of the graph in a nice red hatched pattern (positive numbers) Plot((a<0)*a, "Bears Only" , colorRed|108, ChartLine, StyleWidth2); SetHatchBrush("Percent20", colorWhite|255|colorMintCream|255|161); // Plot a solid black outline around the edge of the graph. Plot(a, "SRME", colorBlack, ChartLine, StyleWidth3); // Plot a black zero line to clearly divide the positive/negative boundary. Plot (0, "", colorBlack, ChartLine, StyleWidth2); Where it fails is when a number crosses the zero line, and I know that it's because I'm calling two different graph functions. But I haven't been able to find a way to create a bi-colored (and hatched) positive/negative graph. Hopefully there's some cool command I'm missing? PS: Try this out on your own positive/negative indicator. It's an attractive plot, IMHO. It just needs a few touch-ups. HELP? :)
 QuantShare 2020-07-05 13:23:47   1 Best Answer Unfortunately, I do not see another way to do this as we do not have a built-in function for that. Note this is happening because when the line drops below 0, instead of drawing say 2, -2 line, you are drawing 2, 0 line.
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